Is there a better way to write this

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,
1 
if item.hp <= item.max_hp / 2: item.hp += 10; if item.hp > item.max_hp: item.hp = item.max_hp
2

What do you mean by better? An alternative is this:

if item.hp <= item.max_hp / 2:
    item.hp += 10
else:
    item.hp = min(item.hp, item.max_hp)
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