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Asked By | Godotuser5675 |
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Reply From: | kozaluss |
In gdscript you do not have control over this. All simple types go as values, all complex types go as reference.
So what should I do if I want to create a swap function.
Godotuser5675 | 2018-09-05 10:33
First You have to have two variables that will keep the reference (may be in array, in class, whatever):
var variable1
var variable2
Then Your swap function must have access to those variables (ex. array, or class) and then you can swap like this:
var tmpvar = variable1
variable1 = variable2
variable2 = tmpvar
And that should be enough to work.
kozaluss | 2018-09-05 12:13
This doesn’t not seem true, I’ve just tested in Godot 3.2
func _ready() -> void:
var derp = Vector2(0,0)
var new_derp = derping(derp)
print("derp ", derp)
print("new_derp ", new_derp)
func derping(value):
value.x = 2
value.y = 1
return value
the printed values are
derp (0, 0)
new_derp (2, 1)
The original variable derp is unchanged so it seems that types like Vector2 are also passed by value… What exactly is a “simple” type?
GabrielM | 2021-01-03 02:28
do you mean built-in types?
GabrielM | 2021-01-03 02:28
Vector2 is comprised of two float components, which is a primitive type.
Everything that extends Object/Node/Reference will be passed by reference, including Array and Dictionary (container data types).
Consider supporting this Godot proposal to be able to swap any variable just like in Python: Add a method to swap two variables in GDScript · Issue #3142 · godotengine/godot-proposals · GitHub
Xrayez | 2021-12-29 13:02
Simple yet powerful answer…
thebluetropics | 2023-02-04 13:23
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Reply From: | TyTYctA |
I think you can use that for passing reference variable.
func _ready():
var a = 1
var b = 2
var c = {
'a': a,
'b': b,}
pass_reference(c)
a = c['a']
b = c['b']
prints(a, b) # a = 3, b = 4
func pass_reference(i_arg:Array):
i_arg[0] = 3
i_arg[1] = 4