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Asked By | jona3717 |
I have an FSM script and another PlayerFSM. The latter inherits from the former.
FSM.gd
var dict : Dictionary
func _ready():
for i in get_children():
dict[i.name] = i
func initialize():
print(dict["some_name"])
PlayerFSM.gd
extends "res://FSM.gd"
func _ready():
initialize()
when i run the scene the only function that gets executed is initialize() and it doesn’t print anything.
What if your PlayerFSM.gd’s ready function is as follows to manually call the _ready function of parent first:
func _ready():
._ready()#call parent's ready first
initialize()
godot_dev_ | 2023-04-23 18:54
When I do that, it throws this error:
Error at (6, 6): Expected statement, found “.” instead.
jona3717 | 2023-04-26 16:52
Hmm, I thought calling the parent class’s functions would work (this
post explains a bit on the idea). It might not work because _ready is a built in function. So my next idea I have would be to use a separate function to define your parent’s _ready logic, as follows
FSM.gd
var dict : Dictionary
func _ready():
readyHook()
func readyHook():
for i in get_children():
dict[i.name] = i
func initialize():
print(dict["some_name"])
and then in the child script, instead of calling _ready, try calling readyHook as follows
PlayerFSM.gd
extends "res://FSM.gd"
func _ready():
readyHook()
initialize()
godot_dev_ | 2023-04-26 18:21
Thank you so much! It is a good solution, it adds some more code, but it seems that with ready it will not be possible.
So the function overloading doesn’t allow the parent’s function to be executed. I am curious if there is a function in godot like python’s init that is executed on import.
jona3717 | 2023-04-28 15:31