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Reply From: |
whiteshampoo |
If i understand correctly, you want to know, if all values in Array 1 are present in Array 2.
Then you could use something like this:
func array_in_array(find : Array, in_array : Array) -> bool:
for value in find:
if not value in in_array:
return false
return true
this iterates over the frist array, and return false if i cant fint it.
if no value returns false, it returns right, because every value has bin found.
Example:
func _ready() -> void:
print(array_in_array([1, 2], [1, 2, 3, 4, 5, 6]))
print(array_in_array([3, 5, 7], [1, 2, 3, 4, 5, 6]))
Output:
True
False
EDIT:
Warning: this can make your game very slow, if you search in big arrays!
Man, firts of all, thanks for your answer. But you misunderstand something. What i need to know is if at least one of the values in Array1 is present in the second Array.
Also: If you can give me a way that also let me know when a single value of the firts Array is twice or more in the Array2, thats will be pretty helpful.
Thanks again. 
you just have to reverse the logic:
instead of return true if all values are present, return false if no values are present
func one_in_array(find : Array, in_array : Array) -> bool:
for value in find:
if value in in_array:
return true
return false
Do you just want to know if something is twice, or do you need to know which?
whiteshampoo | 2020-06-25 05:34
Thanks again man. But what i need to know is how many times is a value of the Array1 in the Array2.
So, if the values of the Array1 are = [“Grass”, “Fire”]
and the values of the Array2 are = [“Grass”, “Water”, “Dragon”, “Grass”]
i need that return 2.
Very similar to the other. But instead of returning true or false, you have to increase a variable:
func count_in_array(find : Array, in_array : Array) -> int:
var found : int = 0
for value in find:
if value in in_array:
found += 1
return found
untested, but should work
whiteshampoo | 2020-06-25 15:53
Man, thank you very much! 
