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Attention | Topic was automatically imported from the old Question2Answer platform. |
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Asked By | AturSams |
You can get all members of a group:
get_tree().get_nodes_in_group("group")
You can get all children:
get_children()
Is there a way to simply get specifically children that are in that group?
Is the only solution to get all children and then filter by their group?
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Reply From: | jgodfrey |
I don’t think there any single, built-in way to do that. I’d probably get the nodes in the group of interest and then get their children. So, something like this:
func _ready():
for node in get_tree().get_nodes_in_group("the_group"):
print(node.name)
for child in node.get_children():
print(" " + child.name)
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Reply From: | Bernard Cloutier |
Is the only solution to get all children and then filter by their group?
Yeah, or the other way around:
var children_in_group = []
for node in get_tree().get_nodes_in_group("the_group"):
if is_a_parent_of(node):
children_in_group.add(node)
Don’t know if this will be useful, but I found this thread first when I looked for a find_child_in_group function, here are the two I created if somebody has use for them
class_name Tools
static func find_child_in_group(parent: Node, group: String, recursive: bool = false):
var output: Node = null
for child in parent.get_children() :
if child.is_in_group(group) :
return child
if recursive :
for child in parent.get_children() :
output = find_child_in_group(child, group, recursive)
if output != null :
return output
return output
static func find_children_in_group(parent: Node, group: String, recursive: bool = false):
var output: Array[Node] = []
for child in parent.get_children() :
if child.is_in_group(group) :
output.append(child)
if recursive :
for child in parent.get_children() :
var recursive_output = find_children_in_group(child, group, recursive)
for recursive_child in recursive_output :
output.append(recursive_child)
return output