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Asked By | Macryc |
HI All. I have a tween set up do shake the clock sprite when timer reaches a certain low value. When the value goes up (after the player has collected a gem) another tween is set off that has a reverse effect to the first one. The conditions for that are in the process function. This works but only once. Ie, the timer goes below 10 - clock does the 1st tween. Timer goes up above 10 - clock does the other tween. But after this, when timer goes back below 10 again, the tweens don’t work… Does tween.start() only work once? Can you somehow ‘reset’ a tween after it has played?
It should be easy enough to do, but it’s hard to point to a problem without seeing the relevant code. Can you post it?
jgodfrey | 2020-02-15 19:58
It’s something like this:
func _process(delta):
powerbar.set_value(MyTimer.time_left)
if powerbar.value <= 10:
tween1.start()
if powerbar.value >= 10:
tween2.start()
Both tweens work once. When timer gets below 10 for the second time, tween1 doesn’t work any more…
Macryc | 2020-02-15 20:24
And, how are those 2 tweens defined?
jgodfrey | 2020-02-15 20:30
Additionally, that logic looks suspect. I mean, powerbar.value would always be either
-
= 10 … or …
- <= 10
So, it seems like you’re firing one (or both when the value = 10) of the two tweens in every frame. I doubt that’s what you want…
jgodfrey | 2020-02-15 20:36
Yea, it took me a moment to realise this. They were firing up 60 times every second, ither one or the other. I put the 2 tweens each it its own function outside of process and set up an on/off toggle ‘mechanism’ with booleans. This solved the problem. Thanks for responding.
Macryc | 2020-02-15 21:45