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Asked By
Volk
As the title suggests I’m having issues with randomized format strings.
So I’ve got a variable set up like so
var desc_color = "There is a {blue} colored hat, a {blue} colored desk, and a {blue} colored critter in the room with you. "
And a function to randomize the format string.
func random_color():
randomize()
var colors = ["blue","azure","sapphire"]
var blue = colors[randi() % colors.size()]
return blue
And for what it’s worth it does manage to print out a random string every time. However it replaces each instance of {blue} with the same item like so.
“There is a sapphire colored hat, a sapphire colored desk, and a sapphire colored critter in the room with you.”
What I’m looking to do is have it randomly select an item from the array for each instance of {blue} so I get a random result for each one.
You could create three separate strings, call the random colour on each and then append them to each other e.g.
var desc_color1 = "There is a {blue} colored hat, "
var desc_color2 = "a {blue} colored desk, "
var desc_color3 = "and a {blue} colored critter in the room with you. "
var desc_color = desc_color1 + desc_color2 + desc_color3
you can then call random colour three different times getting a different result each time.
Would there be a way to do it without splitting everything up into multiple parts? Like through the use of a function or something?
Volk | 2023-02-07 19:58
Well the problem you are having is you need to run the function to return {blue} each time you want a unique example so no matter how you chose to do it this has to be done. For example you could have
var label1 = random_color()
var label2 = random_color()
var label3 = random_color()
var desc_color = "There is a %s colored hat, a %s colored desk, and a %s colored critter in the room with you. " % [label1, label2, label3]
print(desc_color)
This will work but either way you have to call the function 3 different times to get three results.
