Topic was automatically imported from the old Question2Answer platform.
Asked By
nekojita
Hi all! Carrying over some code from a Columns puzzle clone. I’m trying to produce the gdscript equivalent of:
typedef struct TILE
{
int x,y,type;
} TILE;
TILE grid[16][16];
//example
grid[0][0].type = 3
//example
int x = 0;
int y = 0;
for(a = 0; a < 16; a++)
{
for(b = 0; b < 16; b++)
{
grid[a][b].x = x;
grid[a][b].y = y;
y += 16;
}
x += 16;
y = 0;
}
So just a struct to a 2D array, giving the tiles as many properties as desired. Would anyone know how all this might be written in gdscript? Been stumbling on it for a while! Thanks!!
var grid = null
func get_default_tile(): -> Dictionary
var tile = {}
tile.x = 0
tile.y = 0
tile.type = 0
return tile
func get_tile_grid(width, height): -> Array
grid = []
for x in range(width):
grid [x]=[]
for y in range(height):
grid [x][y]= get_default_tile()
return grid
func _ready():
grid = get_tile_grid(16, 16)
# change tile 0, 1:
grid[0][1].x = 100
grid[0][1].y = 200
grid[0][1].type = 10
Thanks! Got it working borrowing a couple changes from a similar Q&A on here for 2D arrays, only now with the dictionary. Going to roll with this and see how it goes!
var grid = null
func get_default_tile() -> Dictionary:
var tile = {}
tile.x = 0
tile.y = 0
tile.type = 0
return tile
func get_tile_grid(width, height) -> Array:
grid = []
for x in range(width):
grid.append([]) #changed from grid [x]=[]
for y in range(height):
grid[x].append(0) #added this
grid[x][y]= get_default_tile()
return grid
func _ready():
grid = get_tile_grid(16, 16)
nekojita | 2019-07-14 15:59
Dictionary is a reference type, so it is not a replacement for struct
