Sorting arrays by size

Help
1

Hi! I think this is a basic question, but I am struggling to find a quick solution. I have three arrays like so:

array_one = [1,2,3,4]
array_two = [1,2]
array_three = [1,2,3,4,5]

I would like to sort them by size and put them into a single array, like this:

arrays_sorted_by_size = [array_three, array_one, array_two]

I am toying with different ideas, but I have the impression I am writing way too much code for something apparently so simple. Any quick tips?

Thanks!

2

Assuming there aren’t too many performance requirements for this, and also assuming you’re going to need to do this more than once:

var src_list = [array_one, array_two, array_three]
var dst_list = []

func sort_by_size(a, b) -> bool:
    if a.size() < b.size():
        return true
    return false

func build_list() -> void:
    src_list.sort_custom(sort_by_size)
    for el in src_list:
        dst_list.append_list(el)

That basically puts all your small lists inside a bigger list where we can sort them by size with sort_custom(). Once we have that, we iterate over them, expanding them into dst_list.

edit: sort_custom(), not custom_sort()…

3 Likes
3

Thanks very much for that. :slight_smile: I knew there had to be a simpler answer to what I was trying.