Wondering about Labels

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1

Godot Version

Godot 4.4

Question

So, I’m trying to make an hp display, and I have a 3 labels, one for the hp, one for the ‘/’ symbol(like, out of) and one for the max hp. My question is, when the text for a label overflows the set boundaries(I don’t know how to explain better, sorry), it adds extra space to the right. So is there a setting to make it so instead of the hp number overflowing into the / symbol, the previous text goes to the left to make space for the new digit?

2

Is there a reason you can’t make it all one label?

3

Sounds much messier than one label. You could use one label and combine several variables into one string.

Lets say variable names are current_hp and max_hp - then you could write str(current_hp) + " / " + str(max_hp) to get the line 7 / 25 to appear on your label.

1 Like
4

Thanks for pointing out I could just use one label, didn’t know I could do that, but there’s still the issue of, for example, if the hp number goes from 5 to 12, the rest of the text is pushed to the right. Any way to make that not happen?

5

You could put the three labels in an HBoxContainer.

1 Like
6

You can use str(num).lpad(2 , "0") if your number is in the single digits to have your label pad a 0 to the left of the value of num. Then when your number is in the double digits you can just have it print str(num) and nothing will shift.

I tried using lpad(2 , " ") but I did it in func _process and it was way too fast for me to notice if it worked. But 0 worked.

    if num >= 0 and num < 10:
      text = str(num).lpad(2 , "0") + " / " +  str(100)
    if num >= 10 and num < 100
      text = str(num) + " / " + str(100)```
2 Likes
7

Hi, if you really want to use the 3 labels. Then you can use a HBoxContainer. Set the horizontal alignment for the hp label to right (the text will go from right to left).

1 label is more preferable. You could have a function that updates the text

var hp: int:
	set(value):
		hp = value
		if is_instance_valid(label):
			update_hp_label(value)
	get:
		return hp


func update_hp_label(value: int):
	label.text = str(value) + "/" + str(max_hp)