Trouble loading save file

Help
,
1

Godot Version

4.4.1 stable

Question

i have a problem with loading my save file using fileaccess, well i did read godot docs and watch
some tutorials and i did come up with this code, and it works, but only with saving, as when i save my game then print room path it works and when i opened save file in notepad it showed correctly but when i exit and play again and load game it doesnt load, next_room_path eventually changes to room_2 path and it saves but it cant load. here is my code.

var next_room_path = "res://Scenes/Rooms/room_1.tscn"
var save_path = "user://file.lol2"

func save_room_to_file(next_room_path)
	var file = FileAccess.open(save_path, FileAccess.WRITE)
	file.store_string(next_room_path)

func load_room_from_file():
	var file = FileAccess.open(save_path, FileAccess.READ)
	var next_room_path = file.get_as_text()
	return next_room_path
func _process(delta: float) -> void:
	if Input.is_action_just_pressed("save"):
		save_room_to_file(next_room_path)
		print("game saved")
	if Input.is_action_just_pressed("load"):
		load_room_from_file()
		print("game loaded")
	if Input.is_action_just_pressed("print_room"):
		print("next room is " + next_room_path)

when i press the load key the output tab prints game loaded but when i press print room key its all wrong.
i also did another method

func save_room_to_file(next_room_path)
	var file = FileAccess.open(save_path, FileAccess.WRITE)
	file.store_var(next_room_path)

func load_room_from_file():
	var file = FileAccess.open(save_path, FileAccess.READ)
	var next_room_path = file.get_var()
	return next_room_path

help me guys i badly want to be able to save/load player progress

2

You’re calling load_room_from_file() but not using the returned value from the function.
This should fix the issue:

if Input.is_action_just_pressed("load"):
    next_room_path = load_room_from_file()
    print("game loaded")

Alternatively, change the function itself to return nothing and set the variable directly:

func load_room_from_file():
    var file = FileAccess.open(save_path, FileAccess.READ)
    next_room_path = file.get_as_text()
2 Likes
3

@sixrobin is right, you may get a warning for “shadowing” your original variable. By using var within the function you are making a new variable with the same name as next_room_path, this new variable is edited then destroyed within the function, totally unused outside it.

var next_room_path = "res://Scenes/Rooms/room_1.tscn"

func load_room_from_file():
	var file = FileAccess.open(save_path, FileAccess.READ)
	# Creates a new next_room_path and deletes it when then function ends
	var next_room_path = file.get_as_text()
	return next_room_path
1 Like
4

thanks bud i solved it using first solution, idk why i did the return option i just saw it in the documentation and did it. i shouldve read about return option because i dont know what does it do.

1 Like
5

Actually, you’ve used this in your code before: when calling FileAccess.open(save_path, FileAccess.WRITE), you store the returned value of the function inside the file variable. Your load_room_from_file() function works the exact same way.

The tricky thing is, even though a function does return a value, it’s not mandatory to store it in a variable. Which is why, even though your function returns next_room_path, you can call the function so that it does its stuff without caring of what it returns.

Anyway, glad I could help :slight_smile: